8.3 Values at Standard Angles (Derivation & Logic)

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Key Formulas

Solved Examples

Step 1

Substitute standard values:

Step 2

cos60=1/2\cos 60^\circ = 1/2, so cos260=1/4\cos^2 60^\circ = 1/4.

Step 3

sec30=2/3\sec 30^\circ = 2/\sqrt{3}, so sec230=4/3\sec^2 30^\circ = 4/3.

Step 4

tan45=1\tan 45^\circ = 1, so tan245=1\tan^2 45^\circ = 1.

Step 5

sin30=1/2\sin 30^\circ = 1/2, cos30=3/2\cos 30^\circ = \sqrt{3}/2.

Step 6

Numerator: 5(1/4)+4(4/3)1=5/4+16/315(1/4) + 4(4/3) - 1 = 5/4 + 16/3 - 1.

Step 7

Denominator: (1/2)2+(3/2)2=1/4+3/4=1(1/2)^2 + (\sqrt{3}/2)^2 = 1/4 + 3/4 = 1 (This is a standard identity).

Step 8

Solve Numerator: LCM of 4, 3 is 12. 15+641212=6712\frac{15 + 64 - 12}{12} = \frac{67}{12}.

Final Answer

67/12

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