2.2 Zeroes of a Polynomial

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Step 1

Let p(x)=x22xp(x) = x^2 - 2x.

Step 2

Evaluate at x=2x = 2: p(2)=(2)22(2)=44=0p(2) = (2)^2 - 2(2) = 4 - 4 = 0. Since p(2)=0p(2) = 0, 2 is a zero.

Step 3

Evaluate at x=0x = 0: p(0)=(0)22(0)=00=0p(0) = (0)^2 - 2(0) = 0 - 0 = 0. Since p(0)=0p(0) = 0, 0 is a zero.

Final Answer

Both 2 and 0 are zeroes.

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