Find the equation of the circle with center (−3,2)(-3, 2)(−3,2) and radius 4.
Here (h,k)=(−3,2)(h, k) = (-3, 2)(h,k)=(−3,2) and r=4r = 4r=4. Equation: (x−(−3))2+(y−2)2=42(x - (-3))^2 + (y - 2)^2 = 4^2(x−(−3))2+(y−2)2=42 (x+3)2+(y−2)2=16(x + 3)^2 + (y - 2)^2 = 16(x+3)2+(y−2)2=16 Expanding: x2+6x+9+y2−4y+4=16x^2 + 6x + 9 + y^2 - 4y + 4 = 16x2+6x+9+y2−4y+4=16 x2+y2+6x−4y−3=0x^2 + y^2 + 6x - 4y - 3 = 0x2+y2+6x−4y−3=0
Find the center and radius of the circle x2+y2−8x+10y−12=0x^2 + y^2 - 8x + 10y - 12 = 0x2+y2−8x+10y−12=0.
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