Find the equation of the line passing through (−2,3)(-2, 3)(−2,3) with slope −4-4−4.
Using Point-Slope Form: y−3=−4(x−(−2))y - 3 = -4(x - (-2))y−3=−4(x−(−2)) y−3=−4(x+2)y - 3 = -4(x + 2)y−3=−4(x+2) y−3=−4x−8y - 3 = -4x - 8y−3=−4x−8 4x+y+5=04x + y + 5 = 04x+y+5=0
Equation of a line is 3x−4y+10=03x - 4y + 10 = 03x−4y+10=0. Find its slope and x- and y-intercepts.
Find the equation of the line whose perpendicular distance from the origin is 4 units and the angle which the normal makes with positive x-axis is 15∘15^\circ15∘.
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