6.5 Advanced JEE Extensions

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Solved Examples

Total ways = 52C4^{52}C_4.

(i) Same Suit: Either all Diamond OR all Club OR all Spade OR all Heart. 13C4+13C4+13C4+13C4=4×13C4^{13}C_4 + ^{13}C_4 + ^{13}C_4 + ^{13}C_4 = 4 \times ^{13}C_4. =4×715=2860= 4 \times 715 = 2860.

(ii) Different Suits: One from each suit. 13C1×13C1×13C1×13C1=134^{13}C_1 \times ^{13}C_1 \times ^{13}C_1 \times ^{13}C_1 = 13^4.

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