11.4 Section Formula

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Solved Examples

Here (x1,y1,z1)=(1,2,3)(x_1, y_1, z_1) = (1, -2, 3), (x2,y2,z2)=(3,4,5)(x_2, y_2, z_2) = (3, 4, -5), m=2,n=3m=2, n=3. x=2(3)+3(1)2+3=6+35=95x = \frac{2(3) + 3(1)}{2+3} = \frac{6+3}{5} = \frac{9}{5} y=2(4)+3(2)2+3=865=25y = \frac{2(4) + 3(-2)}{2+3} = \frac{8-6}{5} = \frac{2}{5} z=2(5)+3(3)2+3=10+95=15z = \frac{2(-5) + 3(3)}{2+3} = \frac{-10+9}{5} = -\frac{1}{5} Point: (95,25,15)(\frac{9}{5}, \frac{2}{5}, -\frac{1}{5}).

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