9.2 Slope of a Line

Calculate Slope $m_1$: $m_1 = \frac{y_2 - y_1}{x_2 - x_1} = \frac{4 - (-2)}{-1 - 3} = \frac{6}{-4} = -\frac{3}{2}$

Check Perpendicularity: Slope of second line $m_2 = \frac{2}{3}$. Product $m_1 m_2 = (-\frac{3}{2}) \times (\frac{2}{3}) = -1$. Conclusion: Yes, the lines are perpendicular.