6.4 Combinations (Order Does Not Matter)

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Solved Examples

  1. Select Boys: Need 3 from 5. Order doesn't matter. 5C3=5×4×33×2×1=10^5C_3 = \frac{5 \times 4 \times 3}{3 \times 2 \times 1} = 10
  2. Select Girls: Need 3 from 4. 4C3=4C1=4^4C_3 = ^4C_1 = 4
  3. Total Ways: By Multiplication Principle (we need boys AND girls): 10×4=40 ways10 \times 4 = 40 \text{ ways}

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