5.4 Applications and Word Problems

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Solved Examples

  1. Given: 30<C<3530 < C < 35.
  2. Substitute Formula: 30<59(F−32)<3530 < \frac{5}{9}(F - 32) < 35
  3. Isolate F:
    • Multiply by 9/5: 30×95<F−32<35×9530 \times \frac{9}{5} < F - 32 < 35 \times \frac{9}{5} 54<F−32<6354 < F - 32 < 63
    • Add 32: 54+32<F<63+3254 + 32 < F < 63 + 32 86<F<9586 < F < 95
  4. Answer: The temperature must be between 86∘86^\circF and 95∘95^\circF.

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