6.3 Permutations (Order Matters)

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Solved Examples

Word: D, A, U, G, H, T, E, R (8 distinct letters). Vowels: A, U, E (3). Consonants: D, G, H, T, R (5).

(i) Together: Treat {A, U, E} as one block 'X'. Objects to arrange: {D, G, H, T, R, X} = 6 objects. Arrangements = 6!=7206! = 720. Internal arrangement of vowels = 3!=63! = 6. Total = 720×6=4320720 \times 6 = 4320.

(ii) Never Together: Total arrangements = 8!=40,3208! = 40,320. Never Together = Total - Together = 40,3204,320=36,00040,320 - 4,320 = 36,000.

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