7.4 Properties of Binomial Coefficients (JEE Foundation)

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Solved Examples

Let P(x)=(1+x3x2)2163=a0+a1x+a2x2+...P(x) = (1+x-3x^2)^{2163} = a_0 + a_1x + a_2x^2 + ... The sum of coefficients is obtained by putting x=1x=1 in the polynomial. Sum = P(1)=(1+13(1)2)2163=(23)2163=(1)2163=1P(1) = (1 + 1 - 3(1)^2)^{2163} = (2-3)^{2163} = (-1)^{2163} = -1.

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