3.9 JEE Advanced Extension: Inequalities & Max/Min

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Solved Examples

  1. Consider part 3cos⁡x+4sin⁡x3 \cos x + 4 \sin x.
  2. Max value = 32+42=5\sqrt{3^2 + 4^2} = 5.
  3. Min value = −5-5.
  4. Adding constant 5: Max = 5+5=105 + 5 = 10. Min = −5+5=0-5 + 5 = 0. Range: [0,10][0, 10].

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